Trang chủ » Hỏi đáp » Môn Toán thu gọn: 5y.(2y-1)-(3y+2).(3-3y) (6x+1)^2-2.(6x+1).(6x-1)+(6x-1)^2 (2x+3)^2-2.(2x+3).(x-2)+(x-2)^2 27/11/2024 thu gọn: 5y.(2y-1)-(3y+2).(3-3y) (6x+1)^2-2.(6x+1).(6x-1)+(6x-1)^2 (2x+3)^2-2.(2x+3).(x-2)+(x-2)^2
1.5y(2y-1)-(3y+2)(3-3y) =10y^2-5y-(9y-9y^2+6-6y) =10y^2-5y-(-9y^2+3y+6) =10y^2-5y+9y^2-3y-6 =19y^2-8y-6 b)(6x+1)^2-2(6x+1)(6x-1)+(6x-1)^2 =[(6x+1)-(6x-1)]^2 =(6x+1-6x+1)^2 =2^2 =4 c)(2x+3)^2-2(2x+3)(x-2)+(x-2)^2 =[(2x+3)-(x-2)]^2 =(2x+3-x+2)^2 =(x+5)^2 =x^2+10x+25 Trả lời
1 bình luận về “thu gọn: 5y.(2y-1)-(3y+2).(3-3y) (6x+1)^2-2.(6x+1).(6x-1)+(6x-1)^2 (2x+3)^2-2.(2x+3).(x-2)+(x-2)^2”