Tìm `x` `(x^2 – 1/2x) : 2x – (3x – 1)^2 : (3x – 1) = 0`

Tìm `x`
`(x^2 – 1/2x) : 2x – (3x – 1)^2 : (3x – 1) = 0`

1 bình luận về “Tìm `x` `(x^2 – 1/2x) : 2x – (3x – 1)^2 : (3x – 1) = 0`”

  1. (x^2 – 1/2x) : 2x – (3x-1)^2 : (3x-1) = 0
    => x^2 : 2x – 1/2x : 2x – (3x-1)=0
    => 1/2x – 1/4 – 3x + 1 = 0
    => (1/2x – 3x) – (1/4 – 1) = 0
    => -5/2x + 3/4 = 0
    => -5/2x = -3/4
    => x = -3/4 : (-5/2)
    => x= -3/4 . (-2/5)
    => x = 3/10
    #FFVN

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