Trang chủ » Hỏi đáp » Môn Toán Tìm `x` `(x^2 – 1/2x) : 2x – (3x – 1)^2 : (3x – 1) = 0` 02/11/2024 Tìm `x` `(x^2 – 1/2x) : 2x – (3x – 1)^2 : (3x – 1) = 0`
(x^2 – 1/2x) : 2x – (3x-1)^2 : (3x-1) = 0 => x^2 : 2x – 1/2x : 2x – (3x-1)=0 => 1/2x – 1/4 – 3x + 1 = 0 => (1/2x – 3x) – (1/4 – 1) = 0 => -5/2x + 3/4 = 0 => -5/2x = -3/4 => x = -3/4 : (-5/2) => x= -3/4 . (-2/5) => x = 3/10 #FFVN Trả lời
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