Tìm x biết: x ( x – 3 ) – 4x + 12 = 0 ⇔ x ( x – 3 ) – 4 ( x – 3 ) = 0 ⇔ ( x – 3 ) ( x – 4 ) = 0 TH1: x – 3 = 0 ⇒ x = 3 TH2: x – 4 = 0 ⇒ x = 4 Vậy x = { 3 ; 4 } color{teal}{\text{Gửi Tus}} Trả lời
a) x(x-3) – 4x + 12 =0 <=> x(x-3) – (4x -12) =0 <=> x(x-3)- 4(x-3) = 0 <=> (x-4)(x-3) =0 <=> \(\left[ \begin{array}{l}x-4=0\\x-3=0\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=4\\x=3\end{array} \right.\) Vậy x in {4;3} #HPHG Trả lời
2 bình luận về “tìm x biết a, x(x-3)-4x+12=0”