p=(1 + 1/x) : (1/x – 1/x-x) + 5/x

2 bình luận về “p=(1 + 1/x) : (1/x – 1/x-x) + 5/x”

1. Giải đáp:

   p=(1+1/x):(1/x-1/x-x)+5/x (Đk: x$\neq$0)

   =(x/x+1/x)/(0-x)+5/x

   =((x+1)/(x))/(-x)+5/x

   =(-(x+1))/(x^2)+5/x

   =(-x-1)/(x^2)+(5*x)/(x*x)

   =(-x-1)/(x^2)+(5x)/(x^2)

   =(-x-1+5x)/(x^2)

   =(4x-1)/(x^2)

   Vậy p=(4x-1)/(x^2)

   Trả lời
2. P = (1 + 1/x) : (1/x – 1/x – x) + 5/x (ĐK : x \ne 0)

   P = (x/x + 1/x ) : (1/x – 1/x – x) + 5/x

   P = (x+1)/x : (0-x) + 5/x

   P =  (x+1)/x  : (-x) + 5/x

   P = [-(x+1)]/(x^2) + 5/x 

   P = (-x-1)/(x^2) + (5x)/(x^2)

   P = (-x-1+5x)/(x^2)

   P = (4x-1)/(x^2) 

   Trả lời