Trang chủ » Hỏi đáp » Môn Toán A = `8/3.5` + `8/5.7` + …. + `8/101.103` 01/04/2024 A = `8/3.5` + `8/5.7` + …. + `8/101.103`
A=[8]/[3.5]+[8]/[5.7]+…+[8]/[101.103] =4.([2]/[3.5]+[2]/[5.7]+…+[2]/[101.103]) =4.([1]/[3]-[1]/[5]+[1]/[5]-[1]/[7]+…+[1]/[101]-[1]/[103]) =4.([1]/[3]-[1]/[103]) =4.[100]/[309] =[4.100]/[309] =[400]/[309] Vậy A=[400]/[309] Trả lời
A = 8/(3.5) + 8/(5.7) + … 8/(101 . 103) A =8/2 . ( (5-3)/(3.5) + (7-5)/(5.7) + … + (103-101)/(101.103)) A = 8/2 . (2/(3.5) + 2/(5.7) + … + 2/(101.103)) A = 4 . ( 1/3 – 1/5 + 1/5 – 1/7 + …. + 1/101 – 1/103) A = 4 . [1/3 + (-1/5 + 1/5) + …… + (-1/101 + 1/101) – 1/103] A = 4.(1/3 – 1/103) A =4 . 100/309 A =400/309 Trả lời
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