phân tích: `10x^2 – 20xy + 10y^2 – 40z^2`

2 bình luận về “phân tích: `10x^2 – 20xy + 10y^2 – 40z^2`”

1. 10x^2-20xy+10y^2-40z^2

   = (10x^2-20xy+10y^2)-40z^2

   = 10(x^2-2xy+y^2)-40z^2

   = 10(x-y)^2-40z^2

   = 10[(x-y)^2-4z^2]

   = 10[(x-y)^2-(2z)^2]

   = 10(x-y-2z)(x-y+2z)

   @Ryan

    

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2. 10x^2 – 20xy + 10y^2 – 40z^2

   = 10 ( x^2 – 2xy + y^2 – 4z^2 )

   = 10 [ ( x – y )^2 – ( 2z )^2 ]

   = 10 ( x – y – 2z ) ( x – y + 2z )

    

   Trả lời