1.. 9(-1/3)^3 -3(-1/3)^2 + 2(-1/3)+1 2.-4/3x=1/3 3.|x-1,5|=1 /2 4. [1,5+(-1/2) ] .3 5.2/3y-1/2=3/4 6. |y-1/3|=0,25 giúp mik v

1 bình luận về “1.. 9(-1/3)^3 -3(-1/3)^2 + 2(-1/3)+1 2.-4/3x=1/3 3.|x-1,5|=1 /2 4. [1,5+(-1/2) ] .3 5.2/3y-1/2=3/4 6. |y-1/3|=0,25 giúp mik v”

1. 1)9(-1/3)^3-3.(-1/3)^2+2.(-1/3)+1

   =9.(-1/27)-3.(1/9)+(-2)/3+1

   =-9/(27)-3/9-2/3+1

   =-1/3-1/3-2/3+1

   =-4/3+1

   =-1/3

   2)-4/3 x=1/3

   <=>x=1/3: -4/3

   <=>x=1/3 .-3/4

   <=>x=-3/(12)

   <=>x=-1/4

   3)|x-1,5|=1/2

   <=>|x-1,5|=0,5

   <=> \(\left[ \begin{array}{l}x-1,5=0,5\\x-1,5=-0,5\end{array} \right.\) 

   <=> \(\left[ \begin{array}{l}x=2\\x=1\end{array} \right.\) 

   Vậy S={1;2}

   4)[1,5+(-1/2)].3

   =(1,5-0,5).3

   =1.3

   =3

   5)2/3 y-1/2=3/4

   <=>2/3 y=3/4+1/2

   <=>2/3 y=5/4

   <=>y=5/4 : 2/3

   <=>y=5/4 . 3/2

   <=>y=(15)/8

   6)|y-1/3|=0,25

   <=>|y-1/3|=1/4

   <=> \(\left[ \begin{array}{l}y-\dfrac{1}{3}=\dfrac{1}{4}\\y-\dfrac{1}{3}=-\dfrac{1}{4}\end{array} \right.\) 

   <=> \(\left[ \begin{array}{l}y=\dfrac{7}{12}\\y=\dfrac{1}{12}\end{array} \right.\) 

   Vậy S={1/(12);7/(12)}

    

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