tìm x 4x^2+4x-3=0 Giúppppppppppppppppppppppppppppppppppppppppp

2 bình luận về “tìm x 4x^2+4x-3=0 Giúppppppppppppppppppppppppppppppppppppppppp”

1. 4x^2 +4x-3=0

   <=>4x^2 +6x-2x-3=0

   <=>2x(2x+3)-(2x+3)=0

   <=>(2x+3)(2x-1)=0

   <=>[(2x+3=0),(2x-1=0):}

   <=>[(2x=-3),(2x=1):}

   <=>[(x=-3/2),(x=1/2):}

   Vậy x in {-3/2;1/2}

    

   Trả lời
2. 4x^2+4x-3=0

   <=> 4x^2 +6x-2x-3=0

   <=> 2x(2x+3)-(2x+3) =0

   <=> (2x-1) (2x+3)=0

   <=> 2x-1=0  hay  2x+3=0

   <=> x= 1/2  hay x= -3/2

   Vậy x = {1/2;-3/2}

    

   Trả lời