a) x = 16 24 b) 2 1 7 5 ( x = + ) ( ) c) ( ) 3 4. 5 7 101 x + = d) 1 2 .3 15 39. x+ + =

a)
x = 16 24
b)
2 1 7 5 ( x = + ) ( )
c)
( )
3
4. 5 7 101 x + =
d)
1
2 .3 15 39. x+
+ =

2 bình luận về “a) x = 16 24 b) 2 1 7 5 ( x = + ) ( ) c) ( ) 3 4. 5 7 101 x + = d) 1 2 .3 15 39. x+ + =”

  1. a) x – 16 = 24
    x = 24 + 16
    x = 40 
    Vậy x = 40
    ———————
    b) 2(x – 1) = 7 + (-5)
    2(x – 1) = 2
    x – 1 = 2 : 2
    x – 1 = 1
    x = 1 + 1
    x = 2
    Vậy x = 2
    ———————–
    c)4 (x + 50)^3 – 7=101
    4(x + 50)^3 = 101 + 7
    4(x + 50)^3 = 108
    (x + 50)^3 = 108 : 4
    (x + 50)^3 = 27
    => (x + 50)^3 = (-3)^3 = 3^3
    TH1 : (x + 50)^3 = (-3)^3
    => x + 50 = -3
    x = -3 – 50
    x = -53
    TH2 : (x + 50)^3 = 3^3
    => x + 50 = 3
    x = 3 – 50
    x = -47
    Vậy x = -47 hoặc x = -53
    ———————————–
    d) 2^(x + 1) . 3 + 15 = 39
    2^(x + 1) . 3 = 39 – 15
    2^(x + 1) . 3 = 24
    2^(x + 1) = 24 : 3
    2^(x + 1) = 8
    => 2^(x + 1) = 2^3
    => x + 1 = 3
    => x = 3 – 1
    x = 2
    Vậy x = 2
    @Chris 

    Trả lời
  2. $\text{a) x – 16 = 24}$
    $\text{⇔ x = 24 + 16 = 40}$
    $\text{Vậy: x = 40}$
    $\text{b) 2(x – 1) = 7 + (-5)}$
    $\text{⇔ 2x – 2 = 2}$
    $\text{⇔ 2x = 2 + 2 = 4}$
    $\text{⇔ x = 2}$
    $\text{Vậy: x = 2}$
    $\text{c) 4(x + 50)³ – 7 = 101}$
    $\text{⇔ 4(x + 50)³ = 101 + 7 = 108}$
    $\text{⇔ (x + 50)³ = 108/4 = 27}$
    $\text{⇔ x + 50 = 27 = 3}$
    $\text{⇔ x = 3 – 50 = -47}$
    $\text{Vậy: x = -47}$
    $\text{d) $2^{x+1}$ .3 + 15 = 39 }$
    $\text{⇔ $2^{x+1}$.3 = 39 – 15 = 24}$
    $\text{⇔ $2^{x+1}$ = 24/3 = 8}$
    $\text{⇔ $2^{x+1}$ = 2³}$
    $\text{⇔ x + 1 = 3}$
    $\text{⇔ x = 3 – 1 = 2}$
    $\text{Vậy: x = 2}$

    Trả lời

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