2/5 +(x -2/3 ) = 5/3 2.(x +4/3) =(1/2)^2 .2/3 (2x -1/3 )^5 =32 /243 4/9 -2/3 x =1/3

2 bình luận về “2/5 +(x -2/3 ) = 5/3 2.(x +4/3) =(1/2)^2 .2/3 (2x -1/3 )^5 =32 /243 4/9 -2/3 x =1/3”

1. Giải đáp:

    \frac{2}{5}+(x-\frac{2}{3})=\frac{5}{3}

   => x-\frac{2}{3}=\frac{5}{3}-\frac{2}{5}

   => x-\frac{2}{3}=\frac{25}{15}-\frac{6}{15}

   => x-\frac{2}{3}=\frac{19}{15}

   => x=\frac{19}{15}+\frac{2}{3}

   => x=\frac{19}{15}+\frac{10}{15}

   => x=\frac{29}{15}

   Vậy x=\frac{29}{15}

   _______________________

   2.(x+\frac{4}{3})=(\frac{1}{2})^{2}.\frac{2}{3}

   =>2.(x+\frac{4}{3})=\frac{1}{4}.\frac{2}{3}

   => 2.(x+\frac{4}{3})=\frac{1}{6}

   => x+\frac{4}{3}=\frac{1}{6}:2

   => x+\frac{4}{3}=\frac{1}{12}

   => x=\frac{1}{12}-\frac{4}{3}

   => x=\frac{1}{12}-\frac{16}{12}

   => x=-\frac{15}{12}

   => x=-\frac{5}{4}

   Vậy x=-\frac{5}{4}

   __________________

   (2x-\frac{1}{3})^{5}=\frac{32}{243}

   => (2x-\frac{1}{3})^{5}=(\frac{2}{3})^{5}

   => 2x-\frac{1}{3}=\frac{2}{3}

   => 2x=\frac{2}{3}+\frac{1}{3}

   => 2x=1

   => x=\frac{1}{2}

   Vậy x=\frac{1}{2}

   _____________________

   \frac{4}{9}-\frac{2}{3}x=\frac{1}{3}

   => \frac{2}{3}x=\frac{4}{9}-\frac{1}{3}

   => \frac{2}{3}x=\frac{4}{9}-\frac{3}{9}

   => \frac{2}{3}x=\frac{1}{9}

   => x=\frac{1}{9}:\frac{2}{3}

   => x=\frac{1}{6}

   Vậy x=\frac{1}{6}

    

   Trả lời
2. Giải đáp:

   2/5 + (x-2/3) = 5/3

   x-2/3 = 5/3 – 2/5

   x – 2/3 = 25/15 – 6/15

   x-2/3 = 19/15

   x = 19/15 + 2/3

   x = 19/15 + 10/15

   x=29/15

   Vậy x=29/15

   $\\$

   2(x+4/3) = (1/2)^2 . 2/3

   2(x+4/3) = 1/4 . 2/3

   2(x+4/3) = 1/6

   x+4/3=1/6 : 2

   x+4/3 = 1/12

   x=1/12 – 4/3

   x = 1/12 – 16/12

   x = -5/4

   Vậy x=-5/4

   $\\$

   (2x – 1/3)^5 = 32/243

   (2x – 1/3)^5 = (2/3)^5

   2x – 1/3=2/3

   2x=2/3 + 1/3

   2x = 1

   x=1:2

   x=1/2

   Vậy x=1/2

   $\\$

   4/9 – 2/3 x = 1/3

   2/3 x = 4/9-1/3

   2/3 x = 4/9 – 3/9

   2/3 x = 1/9

   x = 1/9 : 2/3

   x=1/6

   Vậy x=1/6

    

    

   Trả lời